What happens when the hammer falls during revolver firing?

What happens when the hammer falls during revolver firing?

• A. The primer is struck and ignites the powder charge.
• B. The ejector star resets the cylinder.
• C. The barrel aligns with the target.
• D. The safety engages.

Answer: (A)

When the hammer falls, it strikes the primer of the cartridge, detonating the primer and igniting the powder inside the case. This ignition creates the high-pressure gas that propels the bullet down the barrel. In a double-action revolver, pulling the trigger both cocks the hammer and releases it; in a single-action revolver, you manually cock the hammer before firing. The other options describe actions that aren’t triggered by the hammer fall: the ejector star resets when preparing to eject spent cases; the barrel’s alignment with the target happens as the gun fires and the bullet travels, not from the hammer striking; and safety mechanisms are separate features that aren’t automatically engaged just by the hammer falling.

When the hammer falls, it strikes the primer of the cartridge, detonating the primer and igniting the powder inside the case. This ignition creates the high-pressure gas that propels the bullet down the barrel. In a double-action revolver, pulling the trigger both cocks the hammer and releases it; in a single-action revolver, you manually cock the hammer before firing. The other options describe actions that aren’t triggered by the hammer fall: the ejector star resets when preparing to eject spent cases; the barrel’s alignment with the target happens as the gun fires and the bullet travels, not from the hammer striking; and safety mechanisms are separate features that aren’t automatically engaged just by the hammer falling.